please help me fell a bit of satisfacion

[beginner]

First of all, my english is extremely bad, so maby you will have some difficulties uderstanding my problem. I am beginner in c++ programming, and in programming at all. after few days learning sytax, I wanted to create a program that tests whether a inserted N number can be divided by 2 ( I think you call this number "even numbers", nbt as I said, my english is a weakspot ). So far, I know about the sequence, loops, and conditional statements. Is this a good code:

#include <iostream>

using namespace std;

int main()
{
double Broj, BrojPola, BrojMinus;
char Odg;
do {
cout<< "Unesi jedan prirodan broj: "; //prompt for N number to test
cin>> Broj;
cin.ignore();
BrojPola = Broj / 2; //half of the original number
BrojMinus = BrojPola;
while ( BrojMinus > 0.5 ) {
BrojMinus = BrojMinus - 1;
}
if ( BrojMinus == 0.5 ) {
cout<< "Broj "<< Broj<< " nije paran.\n"; //condition met> !even
}
else {
cout<< "Broj "<< Broj<< " jeste paran.\n"; //reverse ^ comment
}
cout<< "Zelite li da proverite novi broj"
"(d za DA, bilo sta drugo za NE): ";
cin>> Odg;
cin.ignore();
}
while ( Odg == 'd' );
}

[intrest86]

Well, to make life easier, read about the "%" (mod or modulus) operator. It returns the remainder from dividing the left integer by the right integer. For example:

5%2=1
6%2=0
125%11=4

Using that you can use integers to do the test instead of floating point numbers, and not use a loop.

[beginner]

Something like this:

//==============================================

#include <iostream>

using namespace std;

int main()
{
long broj; //The number
short ostatak; //The Remainder
cout<< "Unesi N broj: ";
cin>> broj;
cin.ignore();
ostatak = broj % 2;
if ( ostatak == 0 ) {
cout<< "Broj "<< broj<< " je paran.\n";
}
else {
cout<< "Broje "<< broj<< " je neparan.\n";
}
cin.get();
}

[WbHack]

if "je paran" means even - (or no remainder) - then yes.

by the way, you did use the right word for 2, 4, 6... EVEN.
If you didn't know, the word for numbers like 1, 3, 5... is ODD.